2(x^2-10x+26)=1

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Solution for 2(x^2-10x+26)=1 equation:


Simplifying
2(x2 + -10x + 26) = 1

Reorder the terms:
2(26 + -10x + x2) = 1
(26 * 2 + -10x * 2 + x2 * 2) = 1
(52 + -20x + 2x2) = 1

Solving
52 + -20x + 2x2 = 1

Solving for variable 'x'.

Reorder the terms:
52 + -1 + -20x + 2x2 = 1 + -1

Combine like terms: 52 + -1 = 51
51 + -20x + 2x2 = 1 + -1

Combine like terms: 1 + -1 = 0
51 + -20x + 2x2 = 0

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
25.5 + -10x + x2 = 0

Move the constant term to the right:

Add '-25.5' to each side of the equation.
25.5 + -10x + -25.5 + x2 = 0 + -25.5

Reorder the terms:
25.5 + -25.5 + -10x + x2 = 0 + -25.5

Combine like terms: 25.5 + -25.5 = 0.0
0.0 + -10x + x2 = 0 + -25.5
-10x + x2 = 0 + -25.5

Combine like terms: 0 + -25.5 = -25.5
-10x + x2 = -25.5

The x term is -10x.  Take half its coefficient (-5).
Square it (25) and add it to both sides.

Add '25' to each side of the equation.
-10x + 25 + x2 = -25.5 + 25

Reorder the terms:
25 + -10x + x2 = -25.5 + 25

Combine like terms: -25.5 + 25 = -0.5
25 + -10x + x2 = -0.5

Factor a perfect square on the left side:
(x + -5)(x + -5) = -0.5

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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